The formula of the following silicate anion s | vedclass

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Question

(C) The structure shows $3$ $SiO_4^{4-}$ tetrahedra linked by sharing $2$ oxygen atoms in total. Each of the two terminal $Si$ atoms shares $1$ oxygen

Vedclass · Accepted Answer

$Si_3O_{10}^{8-}$

Vedclass · Answer

(C) The structure shows $3$ $SiO_4^{4-}$ tetrahedra linked by sharing $2$ oxygen atoms in total. Each of the two terminal $Si$ atoms shares $1$ oxygen atom with the central $Si$ atom. Number of $Si$ atoms = $3$. Number of shared oxygen atoms = $2$. Number of unshared oxygen atoms = $3 	imes 4 - 2 	imes 2 = 8$. Total oxygen atoms = $8 + 2 = 10$. The formula is $Si_3O_{10}^{8-}$.

The formula of the following silicate anion structure is,where $\cdot = Si$ atom,$o = O$ atom.

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